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0.05=x^2/2-x
We move all terms to the left:
0.05-(x^2/2-x)=0
Domain of the equation: 2-x)!=0We get rid of parentheses
We move all terms containing x to the left, all other terms to the right
-x)!=-2
x!=-2/1
x!=-2
x∈R
-x^2/2+x+0.05=0
We multiply all the terms by the denominator
-x^2+x*2+(0.05)*2=0
We add all the numbers together, and all the variables
-1x^2+x*2+0.1=0
Wy multiply elements
-1x^2+2x+0.1=0
a = -1; b = 2; c = +0.1;
Δ = b2-4ac
Δ = 22-4·(-1)·0.1
Δ = 4.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{4.4}}{2*-1}=\frac{-2-\sqrt{4.4}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{4.4}}{2*-1}=\frac{-2+\sqrt{4.4}}{-2} $
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